python 的 zipfile 提供了非常便捷的方法来压缩和解压 zip 文件。
例如,在py脚本所在目录中,有如下文件:
readability/readability.js readability/readability.txt readability/readability-print.css readability/sprite-readability.png readability/readability.css
将 readability 目录中的文件压缩到脚本所在目录的 readability.zip 文件中,保持相同的文件结构,然后打印出生成的压缩包 的文件列表,再用两种方式分别解压文件到脚本所在目录的 output 目录和 output/bak 目录中。
脚本如下:
#!/usr/vin/env python # coding: utf-8 \"\"\" 压缩和解压zip文件 \"\"\" import os import zipfile def compress(zip_file, input_dir): f_zip = zipfile.ZipFile(zip_file, \'w\') for root, dirs, files in os.walk(input_dir): for f in files: # 获取文件相对路径,在压缩包内建立相同的目录结构 abs_path = os.path.join(os.path.join(root, f)) rel_path = os.path.relpath(abs_path, os.path.dirname(input_dir)) f_zip.write(abs_path, rel_path, zipfile.ZIP_STORED) def extract(zip_file, output_dir): f_zip = zipfile.ZipFile(zip_file, \'r\') # 解压所有文件到指定目录 f_zip.extractall(output_dir) # 逐个解压文件到指定目录 for f in f_zip.namelist(): f_zip.extract(f, os.path.join(output_dir, \'bak\')) def printdir(zip_file): f_zip = zipfile.ZipFile(zip_file, \'r\') print \'== printdir() ============================\' f_zip.printdir() print print \'== namelist() ============================\' for f in f_zip.namelist(): print f if __name__ == \'__main__\': zip_file = \'readability.zip\' compress(zip_file, os.path.join(os.getcwd(), \'readability\')) printdirzip_file) extract(zip_file, \'output\')
python暴力破解含密码的zip压缩文件
思路:
1.先自己生成一份txt的密码字典
2.然后读取出来,一个个的尝试,当密码错误是,程序会报错中断,所以密码错误,要使用pass
3.当解压缩成功后,中断程序,输出正确密码
import zipfile import os from threading import Thread import time #压缩文件的路径 path = r\'C:\\Users\\Administrator\\Desktop\\moeMaid-master.zip\' #password=\'1234\' def pojie_zip(path,password): if path[-4:]==\'.zip\': #path = dir+ \'\\\\\' +file #print path zip = zipfile.ZipFile(path, \"r\",zipfile.zlib.DEFLATED) #print zip.namelist() try: #若解压成功,则返回True,和密码 zip.extractall(path=\'C:\\\\Users\\\\Administrator\\\\Desktop\\\\\',members=zip.namelist() , pwd=password) print \' ----success!,The password is %s\' % password zip.close() return True except: pass #如果发生异常,不报错 print \'error\' def get_pass(): #密码字典的路径 passPath=\'C:\\\\Users\\\\Administrator\\\\Desktop\\\\zip.txt\' passFile=open(passPath,\'r\') for line in passFile.readlines(): password=line.strip(\'\\n\') print \'Try the password %s\' % password if pojie_zip(path,password): break passFile.close() if __name__==\'__main__\': start=time.clock() get_pass() print \"done (%.2f seconds)\" % (time.clock() - start)
这是我解压缩一个5.4M文件的速度,其实时间都花在了解压缩上了