python 的 zipfile 提供了非常便捷的方法来压缩和解压 zip 文件。

例如,在py脚本所在目录中,有如下文件:

readability/readability.js
readability/readability.txt
readability/readability-print.css
readability/sprite-readability.png
readability/readability.css

将 readability 目录中的文件压缩到脚本所在目录的 readability.zip 文件中,保持相同的文件结构,然后打印出生成的压缩包 的文件列表,再用两种方式分别解压文件到脚本所在目录的 output 目录和 output/bak 目录中。

脚本如下:

#!/usr/vin/env python
# coding: utf-8
\"\"\"
压缩和解压zip文件
\"\"\"

import os
import zipfile

def compress(zip_file, input_dir):
  f_zip = zipfile.ZipFile(zip_file, \'w\')
  for root, dirs, files in os.walk(input_dir):
    for f in files:
      # 获取文件相对路径,在压缩包内建立相同的目录结构
      abs_path = os.path.join(os.path.join(root, f))
      rel_path = os.path.relpath(abs_path, os.path.dirname(input_dir))
      f_zip.write(abs_path, rel_path, zipfile.ZIP_STORED)

def extract(zip_file, output_dir):
  f_zip = zipfile.ZipFile(zip_file, \'r\')

  # 解压所有文件到指定目录
  f_zip.extractall(output_dir)

  # 逐个解压文件到指定目录
  for f in f_zip.namelist():
    f_zip.extract(f, os.path.join(output_dir, \'bak\'))

def printdir(zip_file):
  f_zip = zipfile.ZipFile(zip_file, \'r\')
  print \'== printdir() ============================\'
  f_zip.printdir()
  print
  print \'== namelist() ============================\'
  for f in f_zip.namelist():
    print f

if __name__ == \'__main__\':
  zip_file = \'readability.zip\'
  compress(zip_file, os.path.join(os.getcwd(), \'readability\'))
  printdirzip_file)
  extract(zip_file, \'output\')

python暴力破解含密码的zip压缩文件
思路:

1.先自己生成一份txt的密码字典

2.然后读取出来,一个个的尝试,当密码错误是,程序会报错中断,所以密码错误,要使用pass

3.当解压缩成功后,中断程序,输出正确密码

import zipfile
import os
from threading import Thread
import time
#压缩文件的路径
path = r\'C:\\Users\\Administrator\\Desktop\\moeMaid-master.zip\'
#password=\'1234\'

def pojie_zip(path,password):
 if path[-4:]==\'.zip\':
  #path = dir+ \'\\\\\' +file
  #print path
  zip = zipfile.ZipFile(path, \"r\",zipfile.zlib.DEFLATED)
  #print zip.namelist()
  try:
   #若解压成功,则返回True,和密码
   zip.extractall(path=\'C:\\\\Users\\\\Administrator\\\\Desktop\\\\\',members=zip.namelist() , pwd=password)
   print \' ----success!,The password is %s\' % password
   zip.close()
   return True
  except:
   pass #如果发生异常,不报错
  print \'error\'
  
  
def get_pass():
 #密码字典的路径
 passPath=\'C:\\\\Users\\\\Administrator\\\\Desktop\\\\zip.txt\'
 passFile=open(passPath,\'r\')
 for line in passFile.readlines():
  password=line.strip(\'\\n\')
  print \'Try the password %s\' % password
  if pojie_zip(path,password):
   break
 passFile.close()
if __name__==\'__main__\':
 start=time.clock()
 get_pass()
 print \"done (%.2f seconds)\" % (time.clock() - start)


2015114144628586.jpg (549×133)

这是我解压缩一个5.4M文件的速度,其实时间都花在了解压缩上了