本文实例讲述了Python实现列表转换成字典数据结构的方法。分享给大家供大家参考，具体如下：

\'\'\'
[
  {\'symbol\': 101, \'sort\': 1, \'name\': \'aaaa\'},
  {\'symbol\': 102, \'sort\': 2, \'name\': \'bbbb\'},
  {\'symbol\': 103, \'sort\': 3, \'name\': \'cccc\'},
  {\'symbol\': 104, \'sort\': 4, \'name\': \'dddd\'},
  {\'symbol\': 105, \'sort\': 5, \'name\': \'eeee\'},
  {\'symbol\': 106, \'sort\': 6, \'name\': \'ffff\'},
  {\'symbol\': 107, \'sort\': 7, \'name\': \'gggg\'},
  {\'symbol\': 108, \'sort\': 8, \'name\': \'hhhh\'},
  {\'symbol\': 109, \'sort\': 9, \'name\': \'iiii\'}
]
转换成如下的结构，便于通过ID获取记录值
{
  101: {\'sort\': 1, \'symbol\': 101, \'name\': \'aaaa\'},
  102: {\'sort\': 2, \'symbol\': 102, \'name\': \'bbbb\'},
  103: {\'sort\': 3, \'symbol\': 103, \'name\': \'cccc\'},
  104: {\'sort\': 4, \'symbol\': 104, \'name\': \'dddd\'},
  105: {\'sort\': 5, \'symbol\': 105, \'name\': \'eeee\'},
  106: {\'sort\': 6, \'symbol\': 106, \'name\': \'ffff\'},
  107: {\'sort\': 7, \'symbol\': 107, \'name\': \'gggg\'},
  108: {\'sort\': 8, \'symbol\': 108, \'name\': \'hhhh\'},
  109: {\'sort\': 9, \'symbol\': 109, \'name\': \'iiii\'}
}
\'\'\'
students = [
    {\'symbol\': 101, \'sort\': 1, \'name\': \'aaaa\'},
    {\'symbol\': 102, \'sort\': 2, \'name\': \'bbbb\'},
    {\'symbol\': 103, \'sort\': 3, \'name\': \'cccc\'},
    {\'symbol\': 104, \'sort\': 4, \'name\': \'dddd\'},
    {\'symbol\': 105, \'sort\': 5, \'name\': \'eeee\'},
    {\'symbol\': 106, \'sort\': 6, \'name\': \'ffff\'},
    {\'symbol\': 107, \'sort\': 7, \'name\': \'gggg\'},
    {\'symbol\': 108, \'sort\': 8, \'name\': \'hhhh\'},
    {\'symbol\': 109, \'sort\': 9, \'name\': \'iiii\'}
  ]
symbol_list = map(lambda x: (x.get(\'symbol\'), x), students)
print symbol_list
print \'-----------------------------------------\'
print dict(symbol_list)
#value_list = map(lambda x: x, students)
#
##print dict(zip(symbol_list, value_list))
#
#
#student = {
#    101: {\'symbol\': 101, \'sort\': 1, \'name\': \'aaaa\'}
#    }
#
#student = [
#    {101: {\'symbol\': 101, \'sort\': 1, \'name\': \'aaaa\'}}
#    ]
#

排序用法：

students = [
      {\'name\':\'zhangsan\', \'price\':20.01, \'date\':\'2015-01-09T01:00:00Z\'},
      {\'name\':\'lisi\', \'price\':10.01, \'date\':\'2013-01-09T01:00:00Z\'},
      {\'name\':\'wangwu\', \'price\':0.01, \'date\':\'2012-01-09T01:00:00Z\'}
] 
print sorted(students, key=lambda s:s[\"name\"])
print sorted(students, key=lambda s:s[\"price\"], reverse=True)
print sorted(students, key=lambda s:s[\"date\"], reverse=True)
aa = sorted(students, key=lambda s:s[\"price\"], reverse=True)
sorted(aa, key=lambda s:s[\"date\"], reverse=True)
symbol_arr = [, , ] 
sorted(symbol_arr, key=lambda s:s.amount, reverse=True)

希望本文所述对大家Python程序设计有所帮助。