前些天有位网友建议我在博客中添加RSS订阅功能,觉得挺好,所以自己抽空看了一下如何在Django中添加RSS功能,发现使用Django中的syndication feed framework很容易实现。
具体实现步骤和代码如下:
1、Feed类
# -*- coding: utf-8 -*- from django.conf import settings from django.contrib.syndication.views import Feed from django.utils.feedgenerator import Rss201rev2Feed from blog.models import Article from .constants import SYNC_STATUS class ExtendedRSSFeed(Rss201rev2Feed): mime_type = \'application/xml\' \"\"\" Create a type of RSS feed that has content:encoded elements. \"\"\" def root_attributes(self): attrs = super(ExtendedRSSFeed, self).root_attributes() attrs[\'xmlns:content\'] = \'http://purl.org/rss/1.0/modules/content/\' return attrs def add_item_elements(self, handler, item): super(ExtendedRSSFeed, self).add_item_elements(handler, item) handler.addQuickElement(u\'content:encoded\', item[\'content_encoded\']) class LatestArticleFeed(Feed): feed_type = ExtendedRSSFeed title = settings.WEBSITE_NAME link = settings.WEBSITE_URL author = settings.WEBSITE_NAME description = settings.WEBSITE_DESC + u\"关注python、django、vim、linux、web开发和互联网\" def items(self): return Article.objects.filter(hided=False, published=True, sync_status=SYNC_STATUS.SYNCED).order_by(\'-publish_date\')[:10] def item_extra_kwargs(self, item): return {\'content_encoded\': self.item_content_encoded(item)} def item_title(self, item): return item.title # item_link is only needed if NewsItem has no get_absolute_url method. def item_link(self, item): return \'/article/%s/\' % item.slug def item_description(self, item): return item.description def item_author_name(self, item): return item.creator.get_full_name() def item_pubdate(self, item): return item.publish_date def item_content_encoded(self, item): return item.content
2、URL配置
from django import VERSION if VERSION[0: 2] > (1, 3): from django.conf.urls import patterns, include, url else: from django.conf.urls.defaults import patterns, include, url from .feeds import LatestArticleFeed urlpatterns = patterns( \'\', url(r\'^feed/$\', LatestArticleFeed()), )