本文实例讲述了python实现在无须过多援引的情况下创建字典的方法。分享给大家供大家参考。具体实现方法如下:
1.使用itertools模块
import itertools the_key = [\'ab\',\'22\',33] the_vale = [\'aaaa\',\"dddddddd\",\'22222222222\'] d = dict(itertools.izip(the_key,the_vale)) print d
2.加参数
dict = dict(red = 1,bule = 2,yellow = 3) print dict
结果为:{\’yellow\’: 3, \’bule\’: 2, \’red\’: 1}
3.使用内置的zip函数
zip([iterable,…])返回一个列表,
the_key = [\'ab\',\'22\',33] the_vale = [\'aaaa\',\"dddddddd\",\'22222222222\'] dict2 = dict(zip(the_key,the_vale)) print type(zip(the_key,the_vale)) print dict2
结果:
{33: \'22222222222\', \'ab\': \'aaaa\', \'22\': \'dddddddd\'}
4.dict的fromkeys函数
创建的每个键有相同的value
fromkeys(seq[,value]) Create a new dictionary with keys from seq and values set to value. the_key = [\'ab\',\'22\',33] the_vale = 0 d = dict.fromkeys(the_key,the_vale) print
结果:{33: 0, \’ab\’: 0, \’22\’: 0}
import string count_by_letter = dict.fromkeys(string.ascii_lowercase,0) print count_by_letter
结果:
{\'a\': 0, \'c\': 0, \'b\': 0, \'e\': 0, \'d\': 0, \'g\': 0, \'f\': 0, \'i\': 0, \'h\': 0, \'k\': 0, \'j\': 0, \'m\': 0, \'l\': 0, \'o\': 0, \'n\': 0, \'q\': 0, \'p\': 0, \'s\': 0, \'r\': 0, \'u\': 0, \'t\': 0, \'w\': 0, \'v\': 0, \'y\': 0, \'x\': 0, \'z\': 0}
希望本文所述对大家Python程序设计的学习有所帮助。