本文实例讲述了Python实现基于HTTP文件传输的方法。分享给大家供大家参考。具体实现方法如下：

一、问题：

因为需要最近看了一下通过POST请求传输文件的内容 并且自己写了Server和Client实现了一个简单的机遇HTTP的文件传输工具

二、实现代码：

Server端:

复制代码 代码如下:#coding=utf-8
from BaseHTTPServer import BaseHTTPRequestHandler
import cgi
class   PostHandler(BaseHTTPRequestHandler):
    def do_POST(self):
        form = cgi.FieldStorage(
            fp=self.rfile,
            headers=self.headers,
            environ={\’REQUEST_METHOD\’:\’POST\’,
                     \’CONTENT_TYPE\’:self.headers[\’Content-Type\’],
                     }
        )
        self.send_response(200)
        self.end_headers()
        self.wfile.write(\’Client: %sn \’ % str(self.client_address) )
        self.wfile.write(\’User-agent: %sn\’ % str(self.headers[\’user-agent\’]))
        self.wfile.write(\’Path: %sn\’%self.path)
        self.wfile.write(\’Form data:n\’)
        for field in form.keys():
            field_item = form[field]
            filename = field_item.filename
            filevalue  = field_item.value
            filesize = len(filevalue)#文件大小(字节)
            print len(filevalue)
            with open(filename.decode(\’utf-8\’)+\’a\’,\’wb\’) as f:
                f.write(filevalue)
        return
if __name__==\’__main__\’:
    from BaseHTTPServer import HTTPServer
    sever = HTTPServer((\’localhost\’,8080),PostHandler)
    print \’Starting server, use to stop\’
    sever.serve_forever()
Client端:
复制代码 代码如下:#coding=utf-8
import requests
url = \’http://localhost:8080\’
path = u\’D:快盘阿狸头像.jpg\’
print path
files = {\’file\’: open(path, \’rb\’)}
r = requests.post(url, files=files)
print r.url,r.text

希望本文所述对大家的Python程序设计有所帮助。