很多场景为了不阻塞，都需要异步回调机制。这是一个简单的例子，大家参考使用吧

复制代码 代码如下:
#!/usr/bin/env python
# -*- coding: UTF-8 -*-

import logging
import queue
import threading

def func_a(a, b):
    return a + b

def func_b():
    pass

def func_c(a, b, c):
    return a, b, c

# 异步任务队列
_task_queue = queue.Queue()

def async_call(function, callback, *args, **kwargs):
    _task_queue.put({
        \’function\’: function,
        \’callback\’: callback,
        \’args\’: args,
        \’kwargs\’: kwargs
    })

def _task_queue_consumer():
    \”\”\”
    异步任务队列消费者
    \”\”\”
    while True:
        try:
            task = _task_queue.get()
            function = task.get(\’function\’)
            callback = task.get(\’callback\’)
            args = task.get(\’args\’)
            kwargs = task.get(\’kwargs\’)
            try:
                if callback:
                    callback(function(*args, **kwargs))
            except Exception as ex:
                if callback:
                    callback(ex)
            finally:
                _task_queue.task_done()
        except Exception as ex:
            logging.warning(ex)

def handle_result(result):
    print(type(result), result)

if __name__ == \’__main__\’:
    t = threading.Thread(target=_task_queue_consumer)
    t.daemon = True
    t.start()

    async_call(func_a, handle_result, 1, 2)
    async_call(func_b, handle_result)
    async_call(func_c, handle_result, 1, 2, 3)
    async_call(func_c, handle_result, 1, 2, 3, 4)

    _task_queue.join()