很多场景为了不阻塞,都需要异步回调机制。这是一个简单的例子,大家参考使用吧
复制代码 代码如下:
#!/usr/bin/env python
# -*- coding: UTF-8 -*-
import logging
import queue
import threading
def func_a(a, b):
return a + b
def func_b():
pass
def func_c(a, b, c):
return a, b, c
# 异步任务队列
_task_queue = queue.Queue()
def async_call(function, callback, *args, **kwargs):
_task_queue.put({
\’function\’: function,
\’callback\’: callback,
\’args\’: args,
\’kwargs\’: kwargs
})
def _task_queue_consumer():
\”\”\”
异步任务队列消费者
\”\”\”
while True:
try:
task = _task_queue.get()
function = task.get(\’function\’)
callback = task.get(\’callback\’)
args = task.get(\’args\’)
kwargs = task.get(\’kwargs\’)
try:
if callback:
callback(function(*args, **kwargs))
except Exception as ex:
if callback:
callback(ex)
finally:
_task_queue.task_done()
except Exception as ex:
logging.warning(ex)
def handle_result(result):
print(type(result), result)
if __name__ == \’__main__\’:
t = threading.Thread(target=_task_queue_consumer)
t.daemon = True
t.start()
async_call(func_a, handle_result, 1, 2)
async_call(func_b, handle_result)
async_call(func_c, handle_result, 1, 2, 3)
async_call(func_c, handle_result, 1, 2, 3, 4)
_task_queue.join()