使用python实现递归版汉诺塔示例(汉诺塔递归算法)
利用python实现的汉诺塔。带有图形演示
复制代码 代码如下:
from time import sleep
def disp_sym(num, sym):
print(sym*num, end=\’\’)
#recusion
def hanoi(a, b, c, n, tray_num):
if n == 1:
move_tray(a, c)
disp(tray_num)
sleep(0.7)
else:
hanoi(a, c, b, n-1, tray_num)
move_tray(a, c)
disp(tray_num)
sleep(0.7)
hanoi(b, a, c, n-1, tray_num)
def move_tray(a, b):
for i in a:
if i != 0:
for j in b:
if j != 0:
b[b.index(j) – 1] = i
a[a.index(i)] = 0
return
b.append(i)
b.pop(0)
a[a.index(i)] = 0
return
def disp(tray_num):
global a, b, c
for i in range(tray_num):
for j in [\’a\’, \’b\’, \’c\’]:
disp_sym(5, \’ \’)
eval(\’disp_sym(tray_num – \’ + j + \”[i], \’ \’)\”)
eval(\’disp_sym(\’ + j + \”[i], \’=\’)\”)
disp_sym(1, \’|\’)
eval(\’disp_sym(\’ + j + \”[i], \’=\’)\”)
eval(\’disp_sym(tray_num – \’ + j + \”[i], \’ \’)\”)
print()
print(\’—————————————————————————\’)
tray_num=int(input(\”Please input the number of trays:\”))
tray=[]
for i in range(tray_num):
tray.append(i + 1)
a=[0]*tray_num
b=a[:]
c=a[:]
a = tray[:]
disp(tray_num)
hanoi(a, b, c, tray_num, tray_num)