复制代码 代码如下:
#coding=utf8
__author__ = \’Administrator\’

# 当函数的参数不确定时，可以使用*args和**kwargs。*args没有key值，**kwargs有key值

def fun_var_args(farg, *args):
    print \’args:\’, farg
    for value in args:
        print \’another arg:\’,value

# *args可以当作可容纳多个变量组成的list或tuple
fun_var_args(1, \’two\’, 3, None)

#args: 1
#another arg: two
#another arg: 3
#another arg: None

def fun_var_kwargs(farg, **kwargs):
    print \’args:\’,farg
    for key in kwargs:
        print \’another keyword arg:%s:%s\’ % (key, kwargs[key])

# myarg1,myarg2和myarg3被视为key， 感觉**kwargs可以当作容纳多个key和value的dictionary
fun_var_kwargs(1, myarg1=\’two\’, myarg2=3, myarg3=None)
# 输出：
#args: 1
#another keyword arg:myarg1:two
#another keyword arg:myarg2:3
#another keyword arg:myarg3:None

def fun_args(arg1, arg2, arg3):
    print \’arg1:\’, arg1
    print \’arg2:\’, arg2
    print \’arg3:\’, arg3

myargs = [\’1\’, \’two\’, None]     # 定义列表
fun_args(*myargs)

# 输出：
#arg1: 1
#arg2: two
#arg3: None

mykwargs = {\’arg1\’: \’1\’, \’arg2\’: \’two\’, \’arg3\’: None}      # 定义字典类型
fun_args(**mykwargs)

# 输出：
#arg1: 1
#arg2: two
#arg3: None

# 两者都有
def fun_args_kwargs(*args, **kwargs):
    print \’args:\’, args
    print \’kwargs:\’, kwargs

args = [1, 2, 3, 4]
kwargs = {\’name\’: \’BeginMan\’, \’age\’: 22}
fun_args_kwargs(args,kwargs)
# args: ([1, 2, 3, 4], {\’age\’: 22, \’name\’: \’BeginMan\’})
# kwargs: {}

fun_args_kwargs(1,2,3,a=100)
#args: (1, 2, 3)
#kwargs: {\’a\’: 100}

fun_args_kwargs(*(1,2,3,4),**{\’a\’:None})
#args: (1, 2, 3, 4)
#kwargs: {\’a\’: None}